How to find tangent line at a point
This is a excellent app. 100% has helped me understand and learn by seeing the answer and working my way backwards. It really helps me understand the work I've been set. Very nice application Student must try for their doubts, if you have math class and you can sneak your phone to the test, I can promise this will be the single best app for you.
Santos Phillips
It helped me with alot of things like my module, homework, math, measuring, etc. Really time efficient in helping me with homework, all you have to do is take a picture of the problem then it shows you the answer, i got this app to use for homework, and I was not let down. Super amazing I am a student in math and this will get me higher grades for sure I will definitely recommend this.
James Lockett
Super app, would be better if you could watch an ad which in turn would make the app more money, very good, it even explains how they got the answer instead of just solving it and leaving u clueless on how to solve it. I'm enjoying with my solution and for my subscription it was so fun it also helping me how it is for true kindness I am top class in mathematics gesture.
John Lewis
Enter the equation of a curve and coordinates of the point at which you want to find the tangent line. The tangent line calculator finds the equation of the tangent line to a given curve at a
Get detailed step-by-step answers
If you're looking for detailed, step-by-step answers, you've come to the right place. Our expert team is here to help you with all your questions.
Instant Expert Tutoring
math is all about solving problems, and there's no better feeling than finding the right answer.
Build bright future aspects
As a busy student, I appreciate the convenience and effectiveness of Instant Expert Tutoring.
Decide mathematic tasks
Get math help online by speaking to a tutor in a live chat.
Step - 1: . If the y-coordinate of the point is NOT given, i.e., if the question says the tangent is
Solution : Equation of the given curve is 9x2- 5y2 = 31 18 x - 10 y (dy/dx) = 0 10y (dy/dx) = -18 x dy/dx = -18x / 10 ==> -9x/5 Slope of tangent at the point (2, -1) m = -9 (2)/5 ==> -18/5 So, the